(d-4/4)^2=16

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Solution for (d-4/4)^2=16 equation: 


d in (-oo:+oo)

(d-(4/4))^2 = 16 // - 16

(d-(4/4))^2-16 = 0

(d-1)^2-16 = 0

(d-1)^2-16 = 0

d^2-2*d-15 = 0

d^2-2*d-15 = 0

d^2-2*d-15 = 0

DELTA = (-2)^2-(-15*1*4)

DELTA = 64

DELTA > 0

d = (64^(1/2)+2)/(1*2) or d = (2-64^(1/2))/(1*2)

d = 5 or d = -3

(d+3)*(d-5) = 0

(d+3)*(d-5) = 0

( d+3 )

d+3 = 0 // - 3

d = -3

( d-5 )

d-5 = 0 // + 5

d = 5

d in { -3, 5 }

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